According to Google....0.
You know, with one that accepts more than 9 digits. I'm not surprised it's not arbitrary precision, considering they can't spend too much processing time on it.
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I am the Demon of Delightfulness and Sinister Smirkings!
e^(πi)+1=0
identity named after the Terry Pratchett of 18th century mathematics
I am the Demon of Delightfulness and Sinister Smirkings!
e^(πi)+1=0
identity named after the Terry Pratchett of 18th century mathematics
So what's 399999999999999-399999999999998
16/10/2009 10:02:01 PM
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You'd get the same result on a calculator
16/10/2009 10:20:45 PM
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