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I think it is different snoopcester Send a noteboard - 27/05/2010 03:43:21 PM
So. In the Monty Hall scenario, you have three cards, yadayadayada. All have 1/3 chance of being the right one. You pick one, another is revealed, and you should then switch your card choice.

But.

Does this work on bombs as well?
Say, if you don't know which wire to cut, which is ALWAYS the case. Should you then decide that you think one is the bad wire, cut another one, and then switch your plan and cut the one you originally thought was a bad wire?

And if so, why does that never come up in the kind of shows where there is bomb-defusing going on?


That problem relies in someone picking the card knowing which one it is (ie, not the right one) while you are suggesting a scenario where it is by chance.
*MySmiley*

Robert Graves "There is no money in poetry, but then there is no poetry in money, either."

Henning Mankell "We must defend the open society, because if we start locking our doors, if we let fear decide, the person who committed the act of terror will win"
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/Maths: Question, vaguely related to Monty Hall - 27/05/2010 03:33:51 PM 722 Views
Re: /Maths: Question, vaguely related to Monty Hall - 27/05/2010 03:40:09 PM 943 Views
Re: /Maths: Question, vaguely related to Monty Hall - 27/05/2010 03:41:28 PM 611 Views
I think it is different - 27/05/2010 03:43:21 PM 594 Views
Re: I think it is different - 27/05/2010 03:44:41 PM 646 Views
The first two guys are right *NM* - 27/05/2010 04:23:14 PM 291 Views
Yes - 27/05/2010 04:25:32 PM 638 Views
They have a reason - 27/05/2010 04:27:43 PM 617 Views
This would only work if 2 things are true - 27/05/2010 06:22:59 PM 568 Views

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